Icard (2016): Pragmatic considerations on comparative probability #
Icard asks what is wrong with comparative probability judgments that no probability measure
represents, and answers with a Money Pump without its diachronic step. A subject who prefers
gambles on the events judged likelier, would pay for that preference, and agglomerates the
preferences faces a canonical decision problem against nature, in which the acts gambling on
the likelier side of every strict comparison cost c. Theorem 1 says the uniform mixture Q★
of those acts avoids strict dominance for some cost iff the judgments are representable
(representable_iff_exists_not_dominated), through the Main Lemma (represents_iff_maximizes)
and Pearce's lemma (neverBest_iff_strictlyDominated).
A measure represents the judgments when the order it induces agrees with them (Agree), so each
of the paper's examples fails an axiom of comparative probability. The explorer's cyclic
judgments fail transitivity, Ellsberg's fail de Finetti's quasi-additivity, and the World Cup
judgments of Kraft, Pratt and Seidenberg, which Holliday and Icard also use, satisfy every
de Finetti axiom but are balanced, a failure of Scott's cancellation. When every pair is
judged, representability is the comparative-probability substrate's, and Theorem 1 with Scott's
theorem makes the dominance criterion cancellation (cancellation_iff_exists_not_dominated).
Implementation notes #
- Judgments are a finite family of compared pairs with a
Finsetof strict indices, the paper'sℰ ⊆ ℘(Ω) × ℘(Ω)withXandY; the family may repeat a pair, andX ≠ ∅is a hypothesis where the paper assumes it. A pure act picks a side of each pair, so the paper'sΣisι → Bool. - Mixed acts and beliefs are probability measures. A mixed act's payoff and its expected
utility are integrals against them, the latter the appendix's
𝔼U(Q) = ∑_σ Q(σ) 𝔼U(σ), andQ★is the uniform measure on the preferred acts. - In the refutation direction of the Main Lemma the better mixed act is the pushforward of
Q★along a change of one coordinate rather than the appendix's mixturesQ★*. - Raiffa's options are read through the paper's weights as probabilities that a choice becomes
effective (p. 356): with the coin's weights the preferred act pays
50 − cin every state.
TODO #
- The appendix's mixtures
Q★*for the two cases of the Main Lemma, with the expected-utility differences it displays (p. 369). - Note 25's variant for almost representability, without the cost.
References #
Decision problems against nature #
A uniform mixture pays the average of its acts' payoffs.
The expected payoff of the mixed act μ is the μ-average of the pure acts' expected
payoffs, 𝔼U(Q) = ∑_σ Q(σ) 𝔼U(σ) of the appendix.
Pearce's lemma, the paper's Lemma 2 (p. 361), which it calls folklore in game theory and cites as [Pea84]'s Lemma 3. In a finite decision problem against nature, a mixed act is a best response to no belief iff it is strictly dominated by a mixed act.
Judgments and the canonical decision problem #
A subject's comparative judgments judge, for each compared pair (left i, right i) of
events, left i strictly more likely when i ∈ strict and the two equally likely
otherwise.
- left : ι → Set Ω
The event on the left of comparison
i. - right : ι → Set Ω
The event on the right of comparison
i. - strict : Finset ι
The comparisons judged strict, the paper's
X.
Instances For
A pure act picks, for each compared pair, the side it gambles on, true for left.
Equations
- Icard2016.Act ι = (ι → Bool)
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The stakes of the canonical decision problem are a positive weight and a pair of utilities, good above bad, for each comparison.
- weight : ι → ℝ
The weight of comparison
i. - good : ι → ℝ
The utility of the good outcome of comparison
i. - bad : ι → ℝ
The utility of the bad outcome of comparison
i. - weight_pos (i : ι) : 0 < self.weight i
Instances For
Stakes.const w g b gives every comparison the weight w and the utilities g above b.
Equations
- Icard2016.Stakes.const w g b hw hgb = { weight := fun (x : ι) => w, good := fun (x : ι) => g, bad := fun (x : ι) => b, weight_pos := ⋯, bad_lt_good := ⋯ }
Instances For
Equations
- J.instDecidablePredActPreferred x✝ = Finset.decidableDforallFinset
The preutility of act φ in state ω is the weighted payoff of its gambles.
Equations
- J.preutility s φ ω = ∑ i : ι, s.weight i * if ω ∈ J.side i (φ i) then s.good i else s.bad i
Instances For
The canonical decision problem D_{w,c} charges the preferred acts the cost c.
Equations
- J.utility s c φ ω = J.preutility s φ ω - if J.Preferred φ then c else 0
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The number of preferred acts.
Equations
- J.preferredCard = (Finset.filter J.Preferred Finset.univ).card
Instances For
The uniform mixture Q★ over the preferred acts.
Equations
- J.uniformPreferred = ProbabilityTheory.uniformOn ↑(Finset.filter J.Preferred Finset.univ)
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When every comparison is strict, Q★ is the single act gambling on every left side.
A relation r on events agrees with the judgments, the paper's word for a measure
(p. 368), when it makes each strict comparison strict and each indifference hold both ways.
Equations
Instances For
P represents the judgments (p. 359), P(E) > P(F) on strict comparisons and
P(E) = P(F) on indifferences, when the order it induces agrees with them.
Equations
- J.Represents P = J.Agree P.inducedGe
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The judgments are probabilistically representable.
Equations
- J.Representable = ∃ (P : MeasureTheory.Measure Ω), MeasureTheory.IsProbabilityMeasure P ∧ J.Represents P
Instances For
Judgments that agree with a representable relation are representable.
The Main Lemma #
The P-expected payoff of the unit gamble on side t of comparison i, the paper's
b_{E_i} and b_{F_i}.
Instances For
The expected utility of a pure act is its weighted side values less the cost.
The value of the preferred acts before the cost.
Equations
- J.preferredValue s P = ∑ i : ι, s.weight i * J.sideValue s P i true
Instances For
A preferred act is worth the preferred value under a representing measure.
A non-preferred act loses at least the margin under a representing measure.
Under a representing measure the expected utility of a mixed act is at most the preferred
value less the cost, with equality on Q★.
The pushforward of Q★ along a change of one coordinate beats Q★ when the change never
hurts a preferred act and helps one.
Main Lemma (Lemma 1). A measure represents the judgments iff, for some cost, the uniform preferred act maximizes its expected utility in the canonical decision problem.
Theorem 1 #
Theorem 1. The judgments are probabilistically representable iff, for some cost, the
uniform preferred act Q★ is not strictly dominated in the canonical decision problem.
Balanced judgments #
In each of the paper's examples every state lies in as many left sides as right sides: trading
the preferred gambles for the others "changes nothing whichever team wins" (p. 358). Such
judgments are a failure of Scott's cancellation, so none is representable, and under constant
stakes the trade is a pure act that dominates Q★.
The judged pairs are balanced when every state lies in as many left sides as right sides.
Equations
Instances For
Under constant stakes, the act gambling on every right side pays what the act gambling on every left side pays, in every state, when the judgments are balanced.
Balanced strict judgments leave Q★ strictly dominated under any constant stakes, by the
act that gambles on every right side and pays no cost.
Balanced judgments with a strict comparison are not representable, since a representing measure would give both sides the same total mass yet make each left side at least as heavy and one strictly heavier.
One weak relation on all pairs #
When every pair of events is judged, the paper notes (p. 359) that a single weak relation ≿
records the judgments, with ≻ and ∼ defined from it. Icard's representability is then the
substrate's, so Theorem 1 joins Scott's characterization by cancellation.
ofRel r judges each pair A ≿ B of a weak relation r, strictly when B ≿ A fails and
as an indifference otherwise.
Equations
- One or more equations did not get rendered due to their size.
Instances For
With every pair judged, the judgments of a total relation are representable exactly when the relation is.
A non-trivial monotone relation judges the whole space strictly more likely than ∅.
With every pair judged by a qualitative probability, Scott's cancellation holds exactly when
Q★ avoids strict dominance for some cost, by Theorem 1 joined with Scott's theorem. This makes
precise the paper's remark (p. 350) that the argument justifies the axioms of the representation
theorems "insofar as they are shown to be extensionally equivalent to representability". It
reaches Scott's cancellation, which is equivalent to representability, and not de Finetti's
axioms, which are hypotheses here and fall short of it from five states on.
The examples #
Unit weights and a unit good outcome, the stakes of the explorer and the World Cup.
Equations
Instances For
The explorer (§1, §3, §7) #
The explorer of §1 judges the treasure likelier on island A than B, on B than C, and
on C than A.
Equations
- Icard2016.explorer = { left := ![{0}, {1}, {2}], right := ![{1}, {2}, {0}], strict := Finset.univ }
Instances For
No transitive relation agrees with cyclic judgments, so "given intransitive judgments, there can be no numerical probability measure that agrees with these judgments" (p. 349).
The acts A2, A3, A4 of the table in §7, each gambling on exactly one left side; on the
islands A, B, C they pay 0, 1, 2, 1, 2, 0 and 2, 0, 1.
Equations
- Icard2016.explorerMixture = {![false, false, true], ![false, true, false], ![true, false, false]}
Instances For
The uniform mixture of A2, A3, A4 "guarantees payoff 1 in all states" (p. 365).
In §7 the explorer's preferred act A1 pays 1 − c on every island and is strictly
dominated by the uniform mixture of A2, A3, A4, which pays 1.
Raiffa on Ellsberg (§3) #
In the Ellsberg urn of §3 ([Ell61]), with balls red (0), black (1) and yellow
(2), red is judged likelier than black, and black or yellow likelier than red or yellow.
Equations
- Icard2016.ellsberg = { left := ![{0}, {1, 2}], right := ![{1}, {0, 2}], strict := Finset.univ }
Instances For
The coin-flip weights of Raiffa's comment ([Rai61]), with a hundred utiles at stake.
Equations
Instances For
The Ellsberg judgments violate de Finetti's quasi-additivity (note 7), since adding yellow to both sides of "red over black" gives "red or yellow over black or yellow", which they reverse.
In Raiffa's argument the subject pays to play option 1, gamble 1 on heads and gamble 4 on
tails, over option 2, gambles 2 and 3, although "for both options, the objective probability of
receiving the payoff of 100 is one-half" (p. 355). With the coin's weights the preferred act pays
50 − c whatever the ball and option 2 pays 50.
Kraft, Pratt and Seidenberg's World Cup (§4) #
The World Cup judgments of §4, with Argentina, Brazil, China, Denmark and England as the
worlds 0–4. Denmark is judged likelier than Argentina or China, Argentina or England than
China or Denmark, Brazil or China than Argentina or Denmark, and Argentina, China or Denmark than
Brazil or England.
Equations
- Icard2016.worldCup = { left := ![{3}, {0, 4}, {1, 2}, {0, 2, 3}], right := ![{0, 2}, {2, 3}, {0, 3}, {1, 4}], strict := Finset.univ }
Instances For
The World Cup judgments are not representable, since they are balanced, a failure of cancellation.
In §4's system of bets, trading the four preferred gambles G1, G3, G5, G7 for the
four others changes nothing whichever team wins, so paying for the trade is strict dominance.
(The paper's G2 reads "Argentina or Chile", a slip for China.)
The World Cup teams as Kraft, Pratt and Seidenberg's atoms p, q, r, s, t (0–4), with
Argentina q, Brazil r, China s, Denmark p and England t.
Equations
- Icard2016.worldCupToKps = { toFun := ![1, 2, 3, 0, 4], invFun := ![3, 0, 1, 2, 4], left_inv := Icard2016.worldCupToKps._proof_1, right_inv := Icard2016.worldCupToKps._proof_2 }
Instances For
Note 12. The World Cup judgments agree with a qualitative probability, the Kraft–Pratt–Seidenberg order relabelled, which satisfies quasi-additivity and every other de Finetti axiom; yet neither they nor that order is representable.