Denić (2023): Probabilities and logic in implicature computation #
This file formalizes the two puzzles with embedded disjunction of [Den23] and their
resolution. All 20 of Mary's friends are French or Spanish preferably triggers the
distributive inferences that at least one is French and at least one is Spanish, while Both of
Mary's friends are French or Spanish preferably triggers ignorance about them, (6) and (7), and
fewer disjuncts likewise favour the distributive reading, (8) and (9). Under the exhaustification
of [Fox07], the distributive reading arises when only the disjunction activates its
alternatives, ALT-or, all of which are innocently excludable, and the ignorance reading when the
quantifier does too, ALT-all-or, none of whose alternatives is, (26); since the alternatives
stand in the same entailment relations for any domain size, §3.2, no theory on which
implicatures are a function of entailment can distinguish the two sentences, and the pruning
constraints of [FK11] do not either, §3.3. The proposal, (30), is that an alternative
is pruned the more likely it is given the utterance: with each individual one of the m
properties at random, the probability that some of n individuals is A given that all are one of
the m is 1 − ((m − 1)/m)^n, increasing in n and decreasing in m, and larger than that of the
universal alternative once n > 1, the assumptions of §4; a threshold on it prunes the existential
alternatives of (6) and (8) but not of (7) and (9). The deviance puzzle, §5, is that #Each of
those three girls is Mary, Susan, or Jane is degraded where is called is not: the identity
predicate is singleton-denoting, so given common knowledge the three names are borne by the three
girls one each, every existential alternative is settled, and the ignorance inferences the
sentence triggers contradict common knowledge, (40), the blindness of [Mag09] extended from
scalar to ignorance inferences. Informativeness must then be computed blindly too, §7.3: given
common knowledge the existential alternatives of the deviant sentence are certain and would be
pruned, whereas blind to it their probability lies below every threshold that resolves the
inference puzzle.
Implementation notes #
Worlds assign each of the n individuals exactly one of the m properties, the uniform prior of
§4's assumptions; the prejacent all are one of them is then every world, and the conjunctive
alternatives of the chapter's footnote 8, which it sets aside, are unsatisfiable. The
exhaustification results are the substrate's innocent exclusion over sets of worlds, stated for
every n ≥ 2 and m ≥ 2, the distributive reading itself for two disjuncts. Probabilities are the
uniform measure uniformOn on reals. The mapping from conditional probability to pruning, which
the chapter leaves open between a linear and a threshold form, is taken as a threshold. Ignorance
inferences are the pragmatic ones of §3.1, about every alternative the exhaustified utterance
leaves open, so the grammatical parse of §7.1 is not modelled. The modified-numeral cases of
[BH19], (43), and the symmetry, modal and downward-entailing challenges of §8 are
recorded in the data only.
References #
In the worlds for all of n are A₁ or … or Aₘ each individual has exactly one of the m
properties.
Equations
- Denic2023.World n m = (Fin n → Fin m)
Instances For
All n are Aᵢ, the universal alternative.
Equations
- Denic2023.allAre i = {w : Denic2023.World n m | ∀ (x : Fin n), w x = i}
Instances For
Some of the n are Aᵢ, the existential alternative.
Equations
- Denic2023.someAre i = {w : Denic2023.World n m | ∃ (x : Fin n), w x = i}
Instances For
Under ALT-or only the disjunction activates its alternatives, (24) and (25).
Equations
- Denic2023.altOr n m = Set.range Denic2023.allAre
Instances For
Under ALT-all-or the quantifier activates its alternatives too, (22) and (23).
Equations
- Denic2023.altAllOr n m = Set.range Denic2023.allAre ∪ Set.range Denic2023.someAre
Instances For
The exhaustified utterance leaves an alternative open, entailing neither it nor its negation, so that the maxim of quantity, (19), yields ignorance about it, §3.1.
Equations
- Denic2023.LeavesOpen ALT a = ((Exhaustification.exhIE ALT Set.univ ∩ a).Nonempty ∧ (Exhaustification.exhIE ALT Set.univ ∩ aᶜ).Nonempty)
Instances For
Entailment cannot tell the sentences apart, §3.2 #
With ALT-or every alternative is innocently excludable, for any domain of at least two, since a world with two individuals of different properties falsifies them all.
Exhaustifying with ALT-or over two disjuncts gives the distributive reading (6a), that some are French and some are Spanish.
With ALT-or the existential alternatives are entailed, so no ignorance arises about them, (6b).
With ALT-all-or, the world where everyone is i is minimal, since any world verifying fewer
alternatives would have to falsify all are i and some are i while verifying no other
alternative, and there is no such world.
With ALT-all-or, the world where one individual is i and the rest are k is minimal.
With ALT-all-or no alternative is innocently excludable (26), for any domain of at least two, each universal alternative holding at a minimal constant world and each existential one at a minimal two-property world.
With ALT-all-or exhaustification is vacuous.
With ALT-all-or every alternative is left open, giving ignorance about all of them (7b).
Probabilistic informativeness, §4 #
Under the uniform prior of §4, the probability that some of the n individuals is Aᵢ given
that all are one of the m is 1 − ((m − 1)/m)^n.
The probability that all n individuals are Aᵢ is (1/m)^n.
The more individuals, the likelier that some of them is Aᵢ, §4's assumption (i).
With more than one individual, that some of them is Aᵢ is likelier than that all are,
§4's assumption (ii).
The more disjuncts, the less likely that some individual is A₁, §4's assumption (iii).
In the threshold form of (30), an alternative is pruned when its probability given the utterance reaches the threshold.
Equations
- Denic2023.Pruned θ p = (θ ≤ p)
Instances For
One threshold resolves the inference puzzle. The existential alternatives of all-20-or, (6), and simple-disj, (8), are pruned, leaving ALT-or and the distributive reading, and those of all-2-or, (7), and complex-disj, (9), are kept, leaving ALT-all-or and ignorance.
The deviance puzzle, §5 to §7 #
In the common-knowledge worlds for each of the n girls is one of the n names under the identity copula, the names are borne by different girls.
Equations
- Denic2023.distinct n = {w : Denic2023.World n n | Function.Injective w}
Instances For
A predicate of individuals is singleton-denoting given common knowledge CK (§5) when at
every common-knowledge world it holds of at most one individual.
Equations
- Denic2023.SingletonDenoting CK P = ∀ w ∈ CK, ∀ (x y : Fin n), P w x → P w y → x = y
Instances For
Is Mary is singleton-denoting given that the names are borne by different girls, (37a).
Is called Mary is not singleton-denoting, since two girls may bear the name (37b).
Given common knowledge and the utterance, every name is borne by some girl, since an injection of the n girls into the n names is a surjection.
Common knowledge settles an alternative when it holds or fails at every world compatible with it.
Equations
- Denic2023.Settled CK a = (CK ⊆ a ∨ CK ⊆ aᶜ)
Instances For
Deviant-be (31) is deviant (40) because exhaustification with ALT-all-or leaves every existential alternative open, so ignorance about it is inferred, while common knowledge settles it.
For non-deviant-called (32) the same ignorance is inferred, but common knowledge settles nothing, since the girls may all be called Mary or none may be.
Relative to common knowledge the existential alternatives of deviant-be are certain.
Informativeness must be computed blindly to common knowledge (§7.3). Relative to it the
existential alternatives of deviant-be are certain and any threshold prunes them, which would
leave no ignorance inference and predict no deviance; blind to it their probability is
1 − (2/3)^3, below every threshold that keeps the alternatives of all-2-or, so they survive.