Bilateral Connectives (DN-DRT / BUS) #
Bilateral connectives enabling cross-disjunct anaphora (bathroom sentences), following the DN-DRT / BUS mechanism (@cite{krahmer-muskens-1995}).
This bilateral approach is NOT the same as @cite{hofmann-2025}'s full ICDRT analysis. ICDRT uses static operators over propositional discourse referents to derive accessibility from veridicality + discourse consistency, covering cases (modal subordination, disagreement) that bilateral accounts cannot (§5.1.1).
Main definitions #
BilateralICDRT.neg, disjBathroom, impl, bathroomSentenceFull
DNE for BilateralICDRT: pointwise positive and negative interpretations
of ¬¬φ agree with φ. Routed through the substrate's
Core.Logic.Bilateral.IsBilateral.{positive,negative}_negate_negate,
via BilateralICDRT.isBilateral (parent file).
Negation preserves context consistency.
Standard disjunction without cross-disjunct anaphora.
Equations
- φ ⊕ ψ = { positive := fun (c : Semantics.Dynamic.Core.IContext W E) => φ.positive c ∪ ψ.positive c, negative := fun (c : Semantics.Dynamic.Core.IContext W E) => φ.negative c ∩ ψ.negative c }
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Bathroom disjunction: ψ evaluated in context where φ failed, enabling cross-disjunct anaphora.
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Alternative formulation making the sequencing clearer.
The second disjunct "sees" the context where the first disjunct failed.
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Conditional: if φ then ψ.
In the bathroom analysis, conditionals work similarly: "If there's a bathroom, it's upstairs."
The antecedent introduces drefs accessible in the consequent.
⟦φ → ψ⟧^+ = ⟦φ⟧^- ∪ (⟦φ⟧^+ ∩ ⟦ψ⟧^+) ⟦φ → ψ⟧^- = ⟦φ⟧^+ ∩ ⟦ψ⟧^-
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Material conditional equivalence: φ → ψ ≡ ¬φ ∨ ψ
Using bathroom disjunction, this gives anaphora from antecedent to consequent.
Note: This equivalence requires that ψ's positive update is a subsetting operation (i.e., ψ.positive c' ⊆ c' for any context c'). This is standard in dynamic semantics where updates can only eliminate possibilities, not add them.
De Morgan: ¬(φ ∧ ψ) ≡ ¬φ ∨ ¬ψ
In bilateral semantics, this holds because:
- Negation swaps positive/negative
- Conjunction sequences, disjunction chooses
De Morgan: ¬(φ ∨ ψ) ≡ ¬φ ∧ ¬ψ
Wide-scope existential: ∃x.(φ ∨ ψ)
The variable x is introduced before the disjunction, so it's accessible in both disjuncts.
Equations
- Semantics.Dynamic.Bilateral.ICDRT.BilateralICDRT.existsWideDisj p v domain φ ψ = Semantics.Dynamic.Bilateral.ICDRT.BilateralICDRT.exists_ p v domain (φ.disjBathroom ψ)
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Narrow-scope existential in first disjunct: (∃x.φ) ∨ ψ
With bathroom disjunction, x introduced in ∃x.φ is accessible in ψ because ψ is evaluated in the negative of ∃x.φ, which still introduces x.
Equations
- Semantics.Dynamic.Bilateral.ICDRT.BilateralICDRT.existsNarrowFirstDisj p v domain φ ψ = (Semantics.Dynamic.Bilateral.ICDRT.BilateralICDRT.exists_ p v domain φ).disjBathroom ψ
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Universal quantifier via de Morgan: ∀x.φ ≡ ¬∃x.¬φ
Equations
- Semantics.Dynamic.Bilateral.ICDRT.BilateralICDRT.forall_ p v domain φ = ∼(Semantics.Dynamic.Bilateral.ICDRT.BilateralICDRT.exists_ p v domain ∼φ)
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Bathroom sentence with proper variable reference.
In full ICDRT, "it" in the second disjunct looks up variable v, and the propositional dref p tracks where v has a referent.
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