Documentation

Linglib.Phenomena.Presupposition.Studies.Sharvit2025

Rooth-Partee Conditionals: Empirical Data #

@cite{sharvit-2025} @cite{rooth-partee-1982}Theory-neutral data for @cite{sharvit-2025} "Rooth-Partee Conditionals."

The puzzle #

(85) "If Mia is penniless or proud of her money, Sue shouldn't lend her any."

Two readings:

"Proud of her money" presupposes "Mia has money." Empirically the readings are Strawson-equivalent — speakers cannot distinguish them. Under K/P (material conditional filtering) they are NOT Strawson-equivalent because or^{K/P}(penniless, proud) is undefined at penniless-worlds, causing those worlds to drop from the ∃-reading's quantification domain.

inductive Sharvit2025.W :

Worlds for sentence (85). Cross-product of Mia's financial status (penniless vs has-money-and-proud) with whether Sue lends.

  • pennyNotLend : W
  • pennyLend : W
  • proudNotLend : W
  • proudLend : W
Instances For
    @[implicit_reducible]
    instance Sharvit2025.instDecidableEqW :
    DecidableEq W
    Equations
    @[implicit_reducible]
    instance Sharvit2025.instReprW :
    Repr W
    Equations
    def Sharvit2025.instReprW.repr :
    WStd.Format
    Equations
    Instances For
      @[implicit_reducible]
      instance Sharvit2025.instInhabitedW :
      Inhabited W
      Equations

      "Mia has money" — the presupposition of "proud of her money."

      Equations
      Instances For

        "Mia is penniless" — presuppositionless.

        Equations
        Instances For

          "Mia is proud of her money" — presupposes hasMoney.

          Equations
          Instances For
            @[implicit_reducible]
            Equations

            "Sue shouldn't lend Mia any money" — presuppositionless.

            Equations
            Instances For
              @[implicit_reducible]
              Equations
              @[implicit_reducible]
              Equations

              Penniless entails ¬hasMoney: the presuppositions conflict.

              The disjunction "penniless or proud" under orFilter is UNDEFINED at penniless-worlds. This is the root cause of K/P's failure: orFilter's filtering condition requires "proud of money" to be defined when "penniless" is true, but penniless entails ¬hasMoney.

              @[implicit_reducible]
              Equations

              Under K/P, the ∀-reading is the conjunction of two K/P conditionals.

              Equations
              • One or more equations did not get rendered due to their size.
              Instances For

                K/P ∀-reading: the first conditional (if penniless, shouldntLend) is always defined.

                K/P ∀-reading presup = hasMoney (from the second conditional).

                K/P* conditional: if penniless, shouldntLend.

                Equations
                • One or more equations did not get rendered due to their size.
                Instances For

                  K/P* conditional: if proud-of-money, shouldntLend.

                  Equations
                  • One or more equations did not get rendered due to their size.
                  Instances For

                    K/P* conditional with penniless: always defined.

                    K/P* conditional with proud-of-money: defined iff hasMoney.

                    @[implicit_reducible]
                    Equations

                    K/P* ∃-reading.

                    Equations
                    • One or more equations did not get rendered due to their size.
                    Instances For

                      K/P* ∀-reading.

                      Equations
                      • One or more equations did not get rendered due to their size.
                      Instances For

                        Both K/P* readings have presupposition = hasMoney.

                        Both K/P* readings have identical assertions.

                        Strawson equivalence of ∃ and ∀ readings under K/P*.